OK, I did a little vector diagram of forces. Assuming engine torque of 100 Nm, the tangential force at the PCD of the crank gear is around 2600 N.
There's a similar force on the clutch gear, so the force on the idler bearing is the resultant of those two gear tooth forces.
After more assumptions (like a guestimate of 20? pressure angle on the gear teeth, and using the dimensions of the triple primary drive because I don't have the twin info) and bit of geometry and head scratching, I worked out that the resultant radial force on the idler bearing is about 4080 N (416 kg), trying to jam the gear upwards between the crank and clutch gears. Note that it's an idler, so there's no torsional load on the shaft, and with spur gears (as opposed to helical) there's no axial load either.
I dunno whether my calculation is actually correct because I just came up with the whole theoretical analysis myself in about 10 minutes. A gear train expert might have a better way of doing it, but my sums should be somewhere in the ballpark. I'd be interested to know whether Julian has done a similar calculation, and if so, what he came up with.
But all of that is assuming a constant torsional load at the crankshaft of 100 Nm. In reality there will be some shock loading through the drive train caused by gear changes, rear wheel making or breaking traction, pulling wheelies, snatching of the rear chain during suspension movement, etc. Some of the shock loading would absorbed by the cush drives in the rear hub and clutch, but there will still be some portion of the shocks getting through to the primary drive. So I'd be allowing a reasonably generous safety factor in the design of the bearing supports and the selection of the bearing itself.
When the throttle is closed and the clutch is driving the engine on overrun, the forces are reversed (trying to spit the idler gear out the bottom of the primary case) but they'll be a lot less than when under power because engine braking is effect is a lot less than the power output at full throttle.